Posted by northern gear cutter on June 01, 2009 at 16:11:28:
Hi fellow engineers.
If I have a single helical gear of 56 teeth
16 deg 54 min helix angle
16 dp (pitch of cutter)
3.6579'' (PCD)
3.7829'' (Outside diameter)
How do I work out the outside helix angle, and the helix angle at the base circle ?
Many thanks.
This one has been puzzling me for a while.
Math isnt my strong point.