Posted by Steve Chen on January 21, 2006 at 01:55:17:
In Reply to: Odd teeth over pin measurement posted by Steve Chen on January 20, 2006 at 08:39:44:
My formulas are like the following:
psi/sin(psi+pi/z)=tan^2(betaM)
betaM is helical angle at pin center, it can be caculated this way: tan(betaM)=2xpixrM/T where T is the lead.
find out the psi and then put into the following equation,
Mdp=rMxsqrt(psixsin(psi+pi/z)+2(1+cos(psi+pi/z))+dp
This is for external helical gears, the result is smaller a little bit then the classice formula.
Two pins are not in the same transvers section of gear, but they sit in gear channels steadily.