Posted by BillS on July 18, 2013 at 15:20:04:
In Reply to: Re: Tos fo10 posted by Horacio on July 16, 2013 at 17:01:46:
Many thanks for the information, Horacio.
Sandesh, I used Horacio's information to determine that:
There are 6 index change gears, and the "back" two are on fixed centers, so that the sum of their teeth must be 96.
The ratio of all 6 change gears must always be 24:z. With 48/48 on the back gears, the ratio of the remaining 4 index gears must therefore equal to 24:z as well.
As Horacio points out, you can use 32/64 ratio on the back gears to "shift" the ratio of the main 4 change gears to be 48:z. This is likely necessary when z is a large number.
I tried to include all this information in the FAQ page under Hobbing Machine Constants for a TOS fO10...
Everyone is encouraged to contribute data for hobbing machines that are missing or incomplete in the FAQ page.
Please email me your machine constants - TIA.
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