Posted by David Hollinger on April 05, 2007 at 13:09:57:

I have a question. We have several Barber Colman 6-10 machines. They are machine constants of K=8, K=12, K=18, K=24. When we calculate the feed gears for helical gears, for all machines except the k=18 we use this formula:

Pn/(C*Sine of helix angle)*12/K = feed rate in/rev

This does not work for the K=18 machines. For those machines we have to use this equation:

Pn/(C*Sine of helix angle)= feed rate in/rev

Does anybody know why they are different? The Barber Colman book shows the equation without the 12/K portion, but that gives us gears with NO teeth on the K=8 and K=24. Very curious why the different equations work.

David Hollinger

- Re: Barber Colman 6-10 feed gearing calculations
**Jim***16:43:54 04/05/07*(2)- Re: Barber Colman 6-10 feed gearing calculations
**naveed***09:46:08 06/21/08*(0) - Re: Barber Colman 6-10 feed gearing calculations
**David Hollinger***19:20:57 04/05/07*(0)

- Re: Barber Colman 6-10 feed gearing calculations
- Re: Barber Colman 6-10 feed gearing calculations
**John Cerra***15:54:08 04/05/07*(0)