Posted by lbmakem on February 01, 2006 at 18:41:26:
In Reply to: Helical Gear Problem posted by Stuart on February 01, 2006 at 16:27:34:
(centre's x 2) / (gear teeth + pinion teeth)= module. divide your answer into a smaller module to get the cosine of your helix.
example: (320 x 2) / (22 + 65)=7.3563mod
7mod / 7.3563= .951565 =17.905 degrees.
your gears have been corrected possibaly to prevent undercutting of the pinion?
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