Re: Helical Gear Problem


[ Follow Ups ] [ Post Followup ] [ Meshing with Gears Discussion Forum ] [ FAQ ]

Posted by lbmakem on February 01, 2006 at 18:41:26:

In Reply to: Helical Gear Problem posted by Stuart on February 01, 2006 at 16:27:34:

(centre's x 2) / (gear teeth + pinion teeth)= module. divide your answer into a smaller module to get the cosine of your helix.
example: (320 x 2) / (22 + 65)=7.3563mod
7mod / 7.3563= .951565 =17.905 degrees.
your gears have been corrected possibaly to prevent undercutting of the pinion?


Follow Ups:



Post a Followup

Name:
E-Mail:

Subject:

Comments:

Link URL:
Link Title:
Optional Image URL:


[ Follow Ups ] [ Post Followup ] [ Meshing with Gears Discussion Forum ] [ FAQ ]