Posted by Steve Chen on January 21, 2006 at 01:55:17:

In Reply to: Odd teeth over pin measurement posted by Steve Chen on January 20, 2006 at 08:39:44:

My formulas are like the following:

psi/sin(psi+pi/z)=tan^2(betaM)

betaM is helical angle at pin center, it can be caculated this way: tan(betaM)=2xpixrM/T where T is the lead.

find out the psi and then put into the following equation,

Mdp=rMxsqrt(psixsin(psi+pi/z)+2(1+cos(psi+pi/z))+dp

This is for external helical gears, the result is smaller a little bit then the classice formula.

Two pins are not in the same transvers section of gear, but they sit in gear channels steadily.

- Re: Odd teeth over pin measurement
**lbmakem***13:54:24 01/21/06*(3)- Re: Odd teeth over pin measurement
**Steve Chen***01:53:28 01/22/06*(2)- Re: Odd teeth over pin measurement
**lbmakem***15:43:23 01/22/06*(1)- Formula of it
**Steve Chen***12:26:10 02/09/06*(0)

- Formula of it

- Re: Odd teeth over pin measurement

- Re: Odd teeth over pin measurement